Check: Leap year

help me to solve the error by rewrite the code.

Question : Let "A" be a year, write a program to check whether this year is a leap year or not.

Print "Y" if its a leap year and "N" if its a common year.

My Answer:

A=int(input())

if A%4==0:

print("Y")

else:

print("N")

error:

Traceback (most recent call last):
  File "script-3.8.1.py", line 1, in 
    A=int(input())
EOFError: EOF when reading a line